Viz

02-19-2009, 04:27 PM

Can anybody answer this its Multiplying a Polynomial by a Monomial

3/4k2(8k 2 12k2)

3/4k2(8k 2 12k2)

View Full Version : Help! Algerbra 1

Viz

02-19-2009, 04:27 PM

Can anybody answer this its Multiplying a Polynomial by a Monomial

3/4k2(8k 2 12k2)

3/4k2(8k 2 12k2)

Vontemixmaster

02-19-2009, 04:28 PM

I could I take Algebra 2/Trig. Honors.... but I don't know what that question is saying. Can u post a picture of a piece of paper with the problem on it?

ItalianSoulja

02-19-2009, 04:28 PM

You have to distribute! Then do the stupid FOIL thing!

Vontemixmaster

02-19-2009, 04:29 PM

They are two monomials... cant do that...

ItalianSoulja

02-19-2009, 04:29 PM

Wats the "k" for?

Viz

02-19-2009, 04:35 PM

Here is the pic

http://i40.tinypic.com/6h2gm0.jpg

http://i40.tinypic.com/6h2gm0.jpg

Vontemixmaster

02-19-2009, 04:37 PM

6k (to the 3rd power) -9 (k to the 4th power)

Viz

02-19-2009, 04:43 PM

Thank You for the answer

PRIME

02-19-2009, 04:45 PM

its a odd # look in the back of the book

Vontemixmaster

02-19-2009, 04:52 PM

Thank You for the answer

+rep plz?????????

+rep plz?????????

Merde

02-19-2009, 06:25 PM

First off, write it out better. Second, I'm taking that this year I think

chaosticator@yahoo.com

02-19-2009, 06:34 PM

algerbra.... what a great speller

Pyros

02-19-2009, 08:08 PM

Its been answer but heres a step through:

(3/4)k^2( 8k - 12k^2)

= (3/4)k^2*8k - (3/4)k^2*12k^2

= (24/4)k^3 - (36/4)k^4

= 6k^3 - 9k^4

Pyros

(3/4)k^2( 8k - 12k^2)

= (3/4)k^2*8k - (3/4)k^2*12k^2

= (24/4)k^3 - (36/4)k^4

= 6k^3 - 9k^4

Pyros

vBulletin® v3.8.4, Copyright ©2000-2019, Jelsoft Enterprises Ltd.